Bandit26

bandit level26

ssh server: bandit.labs.overthewire.org port 2220

username: bandit26

password: c7GvcKlw9mC7aUQaPx7nwFstuAIBw1o1

Remember the last challenge when we used the private key for bandit26 we get disconnected, this is what is going to happen this time also.

So again we will reduce the screen size and go into the edit mode of the more command, but this time we not just need to read or edit a file but we need to execute commands, this means we need to use a normal shell type

We can call the bash shell using the  set shell command

Now we can execute any command we want so we will go execute the ls command as advised in the challenge description

We know the usage of bandit27-do

 this is the password for the next level bandit27

tell we meet there

Your comments and feedback are highly appreciated

Thank You

 

Bandit25

bandit level25

ssh server: bandit.labs.overthewire.org port 2220

username: bandit25

password: p7TaowMYrmu23Ol8hiZh9UvD0O9hpx8d

We have no information about this challenge so lets start with finding out what in our home directory.

We have here file named bandit26.sshkey this should be the private key for bandit26 so all we need to do is to connect with this key

$ ssh -i bandit26.sshkey bandit26@localhost -p 2220

The problem here that just after we get connected we disconnect after it shows us the bandit26 banner. In the challenge description there is a hint that the bandit26 shell is not the normal shell, so lets at the first chick the shell type for bandit26 and compare it with bandit25 shell type 

The shell type for bandit26 is a costume shell located in /usr/bin, so we need to read it to understand the behavior

This shell all what it does is showing the contains of a file named text.txt from the root of bandit26 using the more command, then exit the shell.

As we know the more command shows contains that fits the display size then wait for input from the user to show more lines, so we can reduce the screen size and then try again to connect

Instead of asking the shell to show more lines we will ask it to open the editor using the more command "v" argument

Then ask it to edit the bandit26 password fie which stored in the /etc directory

this is the password for the next level bandit26

tell we meet there

Your comments and feedback are highly appreciated

Thank You

 

Bandit24

 

bandit level24

ssh server: bandit.labs.overthewire.org port 2220

username: bandit24

password: VAfGXJ1PBSsPSnvsjI8p759leLZ9GGar

In This challenge there is a listener on port 30002 waiting to receive the bandit24 password followed by a four digits bin code if the values are correct it will replay with the bandit25 password, lets try to connect and submit the values

As you see the system refuses to send the password unless it received the correct combination, bandit24 password and the correct value of the bin code, the problem that we need to find out the secret bin code which means we need to find out the correct value between 10000 iteration.

So we are going to create a script that try the 10000 iteration itself, then open the connection with the listener and try to submit the bandit24 password with the 10000 bin codes line by line until it receives the correct bin code

bandit24pass=VAfGXJ1PBSsPSnvsjI8p759leLZ9GGar

for i in {0..9999}

do

        echo "$bandit24pass $i" >> list

done

nc localhost 30002 <list > results

cat results | grep -v Wrong

This scrip stores the bandit24 password in a variable names bandit24pass, then start a loop that iterates the values starting from "0000" ending with "9999", at every iteration it will create line in a file named "list" the line will be bandit24 password followed by a the value of the loop iteration, at the end we have a file with 10000 line each line has the bandit24 password followed by the four digits bin number, we will connect to the listener on port 30002 using the file "list" and store the response of the listener in a file named "results", finally reading the "results" file searching for any file that doesn't contains the word "Wrong", this will show us the bandit25 password.

don't forget to change the script file permeations to make it executable before running it 

this is the password for the next level bandit25

tell we meet there

Your comments and feedback are highly appreciated

Thank You